x-5x^(1/2)+6=0

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Solution for x-5x^(1/2)+6=0 equation: 


D( x )

x < 0

x < 0

x in <0:+oo)

x-(5*x^(1/2))+6 = 0

x-5*x^(1/2)+6 = 0

t_1 = x^(1/2)

1*t_1^2-5*t_1^1+6 = 0

t_1^2-5*t_1+6 = 0

DELTA = (-5)^2-(1*4*6)

DELTA = 1

DELTA > 0

t_1 = (1^(1/2)+5)/(1*2) or t_1 = (5-1^(1/2))/(1*2)

t_1 = 3 or t_1 = 2

t_1 = 2

x^(1/2)-2 = 0

1*x^(1/2) = 2 // : 1

x^(1/2) = 2

x^(1/2) = 2 // ^ 2

x = 4

t_1 = 3

x^(1/2)-3 = 0

1*x^(1/2) = 3 // : 1

x^(1/2) = 3

x^(1/2) = 3 // ^ 2

x = 9

x in { 4, 9 }

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